Prove it
Theorem: Irrational numbers exist.
Suppose 2^x=5, where x is rational.
Twig
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2026-08-31 14:04:35 UTC
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npub12t6p0pvavfw54460rd4xh47mt07s6gh44rc96jce82y4n5aeycssh0y07hSeen on
wss://relay.momostr.pinkPublished at
2026-08-31 14:04:35 UTCEvent JSON
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